Word Problems About Money Help

As in all word problems, units of measure must be consistent. In the following problems, this means that all money will need to be in terms of dollars or in terms of cents. In the examples that follow, dollars will be used.

Example 1:

Terri has $13.45 in dimes and quarters. If there are 70 coins in all, how many of each coin does she have?

Let x represent the number of dimes. Because the number of dimes and quarters is 70, 70 − x represents the number of quarters. Terri has x dimes, so she has $0.10 x in dimes. She has 70 − x quarters, so she has $0.25(70 − x ) in quarters. These two amounts must sum to $13.45.

Terri has 27 dimes and 70 − x = 70 – 27 = 43 quarters.

Example 2:

Bobbie has $1.54 in quarters, dimes, nickels, and pennies. He has twice as many dimes as quarters and three times as many nickels as dimes. The number of pennies is the same as the number of dimes. How many of each coin does he have?

Nickels are being compared to dimes, and dimes are being compared to quarters, so we will let x represent the number of quarters. Bobbie has twice as many dimes as quarters, so 2 x is the number of dimes he has. He has three times as many nickels as dimes, namely triple 2 x : 3(2 x ) = 6 x . He has the same number of pennies as dimes, so he has 2 x pennies.

How much of the total $1.54 does Bobbie have in each coin? He has x quarters, each worth $0.25, so he has a total of 0.25 x (dollars) in quarters. He has 2 x dimes, each worth $0.10; this gives him 0.10(2 x ) = 0.20 x (dollars) in dimes. Bobbie has 6 x nickels, each worth $0.05. The total amount of money in nickels, then, is 0.05(6 x ) = 0.30 x (dollars). Finally, he has 2 x pennies, each worth $0.01. The pennies count as 0.01(2 x ) = 0.02 x (dollars).

The total amount of money is $1.54, so

Bobbie has 2 quarters; 2 x = 2(2) = 4 dimes; 6 x = 6(2) = 12 nickels; and 2 x = 2(2) = 4 pennies.

A woman had $10,000 to invest. She deposited her money into two accounts—one paying 6% interest and the other interest. If at the end of the year the total interest earned was $682.50, how much was originally deposited in each account?

You could either let x represent the amount deposited at 6% or at . Here, we will let x represent the amount deposited into the 6% account. Because the two amounts must sum to 10,000, 10,000 – x is the amount deposited at . The amount of interest earned at 6% is 0.06 x , and the amount of interest earned at is 0.075(10,000 – x ). The total amount of interest is $682.50, so 0.06 x + 0.075(10,000 – x ) = 682.50.

The woman deposited $4500 in the 6% account and 10,000 – x = 10,000 – 4500 = $5500 in the account.