Cytogenetics Practice Problems Help (page 2)
Review the following concepts if needed:
- Chromosome Structure for Genetics
- Variation in Chromosome Number for Genetics
- Variation in Chromosome Size for Genetics
- Variation in the Arrangement of Chromosome Segments for Genetics
- Variation in the Number of Chromosome Segments for Genetics
- Variation in Chromosome Morphology for Genetics
- Human Cytogenetics for Genetics
Cytogenetics Practice Problems
There are approximately 6:4 × 109 nucleotide pairs per diploid human cell. Each nucleotide pair occupies 3.4 angstroms (Å) of the DNA double helix. If the average length of a human chromosome at metaphase is about 6 micrometers (µm), what is the average packing ratio (i.e., the ratio of extended DNA to condensed DNA lengths)?
The total extended length of DNA per cell is
- (3:4 Å per nucleotide pair) × (6:4 × 109 nucleotide pairs) = 2:2 × 1010 Å
Since 1 Å = 10–10 meter (m), and 100 cm = 1 m,
- 2:2 × 1010 Å × (10–10 m/Å) = 2:2 m or 220 cm
Because there are 23 chromosome pairs in a human diploid cell, the average extended length of DNA per chromosome is 220 cm per 46 chromosomes = 4.8 cm per chromosome. A micrometer is one-millionth of a meter (10–:6 m) or 10–4cm. Thus, the packing ratio of an average human chromosome is
- (Extended DNA length) / (condensed DNA length) = 4:8 cm/(6 × 10–4 cm)
- = 8:0 × 103
or 8000 times longer when extended than when condensed in metaphase.
Suppose that an autotetraploid of genotype AAaa forms only diploid gametes by random assortment from the quadrivalents (formed by synapsis of four chromosomes) during meiosis. Recall that chromosomes separate during the first meiotic division; sister chromatids separate during the second meiotic division. The A locus is so close to the centromere that crossing over in this region is negligible. (a) Determine the expected frequencies of zygotic genotypes produced by selfing the autotetraploid. (b) Calculate the expected reduction in the frequency of progeny with a recessive phenotype in comparison with that of a selfed diploid of genotype Aa.
- Let us identify each of the four genes as follows: A1, A2, a1, a2 (A1 and A2 represent identical dominant alleles; a1 and a2 represent identical recessive alleles at the A locus).
- If one dose of the dominant allele is sufficient to phenotypically mask one or more doses of the recessive allele, then the phenotypic ratio is expected to be 35A: 1a. One-quarter of the offspring of a selfed diploid heterozygote (Aa) is expected to be of the recessive phenotype. The reduction in the frequency of the recessive trait is from 1/4 to 1/36, or ninefold. When homozygous genotypes produce a less desirable phenotype than heterozygotes, polyploidy can act as a buffer to reduce the incidence of homozygotes.
For genes that are tightly linked to their centromeres, the distribution of alleles into gametes follows the same pattern as chromosomal assortment. Let us first use a checkerboard to determine the kinds and frequencies of different combinations of alleles in pairs expected in the diploid gametes of the autotetraploid.
Because sister chromotids separate at meiosis II, the diagonal of the above table represents the nonexistent possibility of a given chromosome (or identical allele) with itself in a gamete. The table is symmetrical on either side of the diagonal. Ignoring the superscript identification of alleles, the expected ratio of possible diploid gametes is 1 AA : 4 Aa : 1 aa = 1/6 AA : 2/3 Aa : 1/6 aa. Using these diploid gametic expectations, let us now construct a zygotic checkerboard for the prediction of tetraploid progeny genotypes.
Ratio of offspring genotypes: 1/36 AAAA (quadruplex): 8/36 AAAa (triplex): 18/36 AAaa (duplex): 8/36 Aaaa (simplex): 1/36 aaaa (nulliplex)
Assume that an autotetraploid of genotype AAaa has the A locus 50 ormore map units from the centromere, so that the equivalent of a single crossover always occurs between the centromere and the A locus. In this case, the chromatids will assort independently. Further assume that random assortment of chromatids to the gametes occurs by twos. Determine (a) the expected genotypic ratio of the progeny that results from selfing this autotetraploid, and (b) the expected increase in the incidence of heterozygous genotypes compared with selfed diploids of genotype Aa.
- Let each of the genes of the duplex tetraploid be labeled as shown in the illustration below. All capital letters represent identical dominant genes; all lowercase letters represent identical recessive alleles.
- The total of the numbers (3 + 8 + 3) along the top or side of the preceding table is 14. Thus, the total of all crossproducts in the table is 14 × 14 = 196. Nine genotypes are homozygous AAA, and another nine are homozygous aaaa.Thus, all other genotypes (196 – 18 = 178) are heterozygotes. Selfing the autotetraploid produces 178/196 = 91% heterozygous progeny. Selfing a diploid of genotype Aa produces 50% heterozygous progeny. The increase from 50 to 91% is 41/50 = 82%
As in Practice 2, let us first use a Punnett square to determine the kinds and frequencies of different combinations of alleles (in pairs) expected in the gametes of the autotetraploid. Note in the illustration that (for example) alleles A1 and A2, originally on sister chromatids, can enter the same gamete if crossing over occurs between the centromere and the A locus. Likewise, any other pair of alleles could enter a gamete by the same mechanism (chromatid assortment). Random assortment (by twos) of eight chromatids of the autotetraploid during meiosis is shown in the following table. Note that the diagonal of the table represents the nonsense union of any given allele with itself (e.g., A1 with A1). The table is symmetrical on either side of the diagonal.
Ignoring the superscript identification of alleles, the expected ratio of possible diploid gametes is 6 AA: 16 Aa: 6 aa or 3 : 8: 3. Using these gametic expectations, we can now construct a zygotic checkerboard to generate the expected progeny. Summary of progeny genotypes: 9 AAAA (quadruplex) : 48 AAAa (triplex) : 82 AAaa (duplex) : 48 Aaaa (simplex) : 9 aaaa (nulliplex).
Pericarp is the outermost layer of the corn kernel and is maternal in origin. A dominant gene B produces brown pericarp, and its recessive allele b produces colorless pericarp. Tissue adjacent to the pericarp is aleurone (triploid). Purple pigment is deposited in the aleurone when the dominant gene C is present; its recessive allele c results in colorless aleurone. Aleurone is actually a single specialized layer of cells of the endosperm. The color of endosperm itself is modified by a pair of alleles. Yellow is governed by the dominant allele Y and white by the recessive allele y. Both C and Y show xenia to their respective alleles. A plant that is bbCcYy is pollinated by a plant of genotype BbCcYy. (a) What phenotypic ratio is expected among the progeny kernels? (b) If the F1 is pollinated by plants of genotype bbccyy, in what color ratio will the resulting F2 kernels be expected to appear?
- If pericarp is colorless, then the color of the aleurone shows through. If aleurone is also colorless, then the color of the endosperm becomes visible. Since the maternal parent is bb, the pericarp on all F1 seeds will be colorless. Any seeds with C will have purple aleurone. Only if the aleurone is colorless (ccc) can the color of the endosperm be seen.
- Half of the F1 embryos is expected to be Bb and will thus lay down a brown pericarp around their seeds in the F2; the other half is expected to be bb and will envelop its seeds with a colorless pericarp. Thus, half of the seeds of the F1 plants will be brown. Of the remaining half that has colorless pericarp, we need show only as much of the genotype as is necessary to establish the phenotype.
- Summary of F2 seed colors : 1/2 brown : 1/4 purple: 1/8 yellow: 1/8 white.
In 1931, Curt Stern found two different translocations in Drosophila from which he developed females possessing heteromorphic X chromosomes. One X chromosome had a piece of the Y chromosome attached to it; the other X was shorter and had a piece of chromosome IV attached to it. Two sex-linked genes were used as markers for detecting crossovers; the recessive trait carnation eye color (car) and the dominant trait bar eye (B). Dihybrid bar females with heteromorphic chromosomes (both mutant alleles on the X portion of the X-IV chromosome) were crossed to hemizygous carnation males with normal chromosomes. The results of this experiment provided cytological proof that genetic crossing over involves an actual physical exchange between homologous chromosome segments. Diagram the expected cytogenetic results of this cross showing all genotypes and phenotypes.
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