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# Geometry Word Problems Practice Problems (page 2)

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Updated on Aug 24, 2011

### Solutions

1. Read the entire word problem.
2. We are given the measure of one of two alternating angles.

We are looking for the measure of the other alternating angle.

Underline the keywords and words that indicate formulas.

The word alternating tells us that angles 1 and 2 are congruent—their measures are the same.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

We don't need to perform any operations or write any number sentences. Alternating angles are congruent, so since angle 2 is 110°, angle 1 is 110°.

We didn't perform any operations, so we don't have any work to check. Alternating angles are also known as corresponding angles, and the definition of corresponding angles is two or more congruent angles that have similar positions in a shape or figure. Our answer is correct.

3. Read the entire word problem.
4. We are given the measure of angle F and told that it forms a right angle with angle G.

We are looking for the measure of angle G.

Underline the keywords and words that indicate formulas.

The phrase right angle tells us that angles F and G are complementary—their measures sum to 90°.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

Since angles F and G are complementary, we must subtract the measure of angle F from 90° to find the measure of angle G.

Write number sentences for each operation.

90 – 42

Solve the number sentences and decide which answer is reasonable.

90 – 42 = 48°

There are 90° in a right angle, so the measures of angles F and G should add up to 90: 42 + 48 = 90°.

5. Read the entire word problem.
6. We are given the measure of angle 2 and told that angles 1 and 2 are supplementary. We are also told that angles 1 and 3 are vertical.

We are looking for the measure of angle 3.

Underline the keywords and words that indicate formulas.

The word supplementary tells us that the measures of angles 1 and 2 add up to 180°, and the word vertical tells us that angles 1 and 3 are congruent.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

Since angles 1 and 2 are supplementary, we must subtract the measure of angle 2 from 180° to find the measure of angle 1.

Write number sentences for each operation.

180 – 56

Solve the number sentences and decide which answer is reasonable.

180 – 56 = 124°

Angle 1 is 124°. Angles 1 and 3 are vertical angles, so angle 3 is also 124°.

We can check that angle 1 is 124° by adding its measure to the measure of angle 2, since these angles are supplementary: 124 + 56 = 180°. Vertical angles are defined as congruent angles that are formed by the intersection of two lines, so angle 3 does, in fact, equal angle 1.

7. Read the entire word problem.
8. We are given the measures of two angles of a triangle.

We are looking for the name of this kind of triangle.

Underline the keywords and words that indicate formulas.

There are no keywords in this problem.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The two angle measures are not 60° and they are not equal, so this triangle is not equilateral or isosceles. We must add the two angles together and subtract from 180° to find the measure of the third angle. Then, we will be able to determine if the triangle is acute, obtuse, or right.

Write number sentences for each operation.

First, add the two given angles:

13 + 77

Solve the number sentences and decide which answer is reasonable.

13 + 77 = 90°

Subtract this sum from 180°, the number of degrees in a triangle, to find the measure of the third angle.

Write number sentences for each operation.

180 – 90

Solve the number sentences and decide which answer is reasonable.

180 – 90 = 90°

The third angle of the triangle is a right angle, which means that this is a right triangle.

We can check that the three angles add to 180°; 13 + 77 + 90 = 180°, so the third angle is, in fact, a right angle, and this triangle is a right triangle.

9. Read the entire word problem.
10. We are given the measure of one angle of an isosceles triangle.

We are looking for the measures of the other two angles.

Underline the keywords and words that indicate formulas.

The keyword isosceles tells us that two angles in the triangle are congruent.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The given angle is 100°. It cannot be one of the base angles of the triangle, because there cannot be two obtuse angles in a triangle (since there are only 180° in a triangle). The other two angles must be the base angles. Subtract the measure of the given angle from 180° to find the total measure of the other two angles. Then, divide that difference by 2 to find the measure of each of those angles.

Write number sentences for each operation.

First, subtract 100 from 180:

180 – 100

Solve the number sentences and decide which answer is reasonable.

180 – 100 = 80°

The two base angles combined equal 80°. Divide 80 by 2 to find the measure of each base angle.

Write number sentences for each operation.

Solve the number sentences and decide which answer is reasonable.

The other two angles each measure 40°.

We can check that the three angles add up to 180°: 100 + 40 + 40 = 180°. The three angles total 180°, and two of the angles are the same in measure, so our answer is correct.

11. Read the entire word problem.
12. We are given the area and the height of a triangle.

We are looking for its base.

Underline the keywords and words that indicate formulas.

The keywords base, area, height, and triangle tell us that we need to use the formula for area of a triangle.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

We are given the area and the height. We can rewrite the formula A = by dividing both sides of . The base, b, is equal to .

Write number sentences for each operation.

First, multiply the area by 2:

2(48)

Solve the number sentences and decide which answer is reasonable.

2(48) = 96 square units

Write number sentences for each operation.

Now, divide that by the height:

Solve the number sentences and decide which answer is reasonable.

The base of the triangle is 9.6 units.

Since A = , check that half the product of the base and the height equals the area, 48 square units: square units.

13. Read the entire word problem.
14. We are given the measures of the bases and the longest side of an isosceles triangle.

We are looking for the perimeter of the triangle.

Underline the keywords and words that indicate formulas.

We are asked to find the perimeter, and the keywords isosceles triangle tell us that the base angles of the triangle are equal. We have been given all three sides of the triangle, and we must add them to find the perimeter.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The perimeter of a triangle is equal to the sum of the lengths of the sides, so we must add.

Write number sentences for each operation.

14 + 14 + 20

Solve the number sentences and decide which answer is reasonable.

14 + 14 + 20 = 44 inches

The perimeter of the triangle is 44 inches.

Since the triangle is isosceles, if we subtract base lengths from the perimeter, we should be left with the other side of the triangle, which is 20 inches long: 44 – 12 – 12 = 20 inches.

15. We are told that the angles of triangles JKL and MNO are identical, which means that they are similar triangles. Draw and label triangles JKL and MNO:

We can use a proportion to find the length of side MN. Since the area of triangle JKL is four times the area of triangle MNO, the ratio of their sides . Cross multiply and divide: 4MN = 16, MN = 4 meters.

16. Read the entire word problem.
17. We are given the measures of one leg and the hypotenuse of a right triangle.

We are looking for the measure of the other leg.

Underline the keywords and words that indicate formulas.

We are told we are working with a right triangle, which the word hypotenuse also indicates.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

Since we have a right triangle and the lengths of two sides, we can use the Pythagorean theorem to find the length of the missing side. Rewrite the formula a2 + b2 = c2 as b2 = c2a2, since we are looking for the length of a leg.

Write number sentences for each operation.

First, find the difference between the square of the hypotenuse and the square of one leg:

(10)2 – (6)2

Solve the number sentences and decide which answer is reasonable.

(10)2 – (6)2 = 100 – 36 = 64

Write number sentences for each operation.

The square of the leg is 64, so to find the length of the leg, we must take the square root of 64: √64

Solve the number sentences and decide which answer is reasonable.

64 = 8

The length of the other leg is 8 centimeters.

The square of the hypotenuse should equal the sum of the squares of the legs: (6)2 + (8)2 = (100)2, 36 + 64 = 100, 100 = 100.

18. Read the entire word problem.
19. We are given the measures of one leg of a triangle.

We are looking for the measure of the hypotenuse.

Underline the keywords and words that indicate formulas.

The word hypotenuse indicates we are working with a right triangle.

Since the triangle is also isosceles, it must be an isosceles right triangle.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

Since the triangle is isosceles, both legs are 8 feet. Use the formula a2 + b2 = c2 to find c, the length of the hypotenuse. We will need to square the legs and add those squares. Then, we will need to take the square root of that sum.

Write number sentences for each operation.

First, square the legs and add them:

(8)2 + (8)2

Solve the number sentences and decide which answer is reasonable.

(8)2 + (8)2 = 64 + 64 = 128

Write number sentences for each operation.

The square of the hypotenuse is 128, so to find the length of the hypotenuse, we must take the square root of 128:

128

Solve the number sentences and decide which answer is reasonable.

128 = 8√2 feet.

The hypotenuse of triangle ABC is 8√2 feet.

The square of the hypotenuse should equal the sum of the squares of the legs: (8)2 + (8)2 = (8√2)2, 64 + 64 = 128.

20. Read the entire word problem.
21. We are told that a quadrilateral has four right angles.

We are looking for the type of quadrilateral that it could be.

Underline the keywords and words that indicate formulas.

The keywords four right angles tell us that this quadrilateral is either a rectangle or a square.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

There are no operations to perform. A rectangle has four right angles, and a square is a type of rectangle, so this quadrilateral could be a square or a rectangle.

The definition of a rectangle is a parallelogram with four congruent, 90° angles and congruent diagonals, and a square is a rectangle, so this answer is correct.

22. Read the entire word problem.
23. We are told that a quadrilateral has perpendicular diagonals that are not congruent.

We are looking for the type of quadrilateral that it could be.

Underline the keywords and words that indicate formulas.

The keywords perpendicular diagonals tell us that this quadrilateral is a rhombus or a square, and the keywords not congruent tell us that it is not a square, since the diagonals of a square are congruent.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

There are no operations to perform. A rhombus has perpendicular diagonals, as does a square since a square is a type of rhombus. But a square has congruent diagonals, so this quadrilateral must be a rhombus.

The definition of a rhombus is a parallelogram with four congruent sides and perpendicular diagonals that bisect their angles, while a square has all of the properties of a rhombus and a rectangle, and the diagonals of a rectangle are congruent.

24. Read the entire word problem.
25. We are given the measures of the bases and height of a trapezoid.

We are looking for the area of the trapezoid.

Underline the keywords and words that indicate formulas.

The words area and trapezoid indicate that we must use the formula for area of a trapezoid: .

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

First, we must add the bases and multiply by one-half. Then, we must multiply that product by the height.

Write number sentences for each operation.

(16 + 10)

Solve the number sentences and decide which answer is reasonable.

(16 + 10) = (26) = 13 meters

Write number sentences for each operation.

Now multiply that product by the height, 4:

(13)(4)

Solve the number sentences and decide which answer is reasonable.

(13)(4) = 52 meters

The area of the trapezoid is 52 meters.

Divide the area by half the sum of the baseotient should equal the height, 4 meters: 4 meters.

26. Read the entire word problem.
27. We are given the area and height of a rhombus.

We are looking for its base.

Underline the keywords and words that indicate formulas.

The words area and rhombus indicate that we must use the formula for area of a parallelogram, since a rhombus is a parallelogram: A = bh.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

Rewrite the formula to solve for b, the base of the rhombus: b = .

Divide the area by the height.

Write number sentences for each operation.

Solve the number sentences and decide which answer is reasonable.

= 13 centimeters

The base of the rhombus is 13 centimeters.

Since the area of a rhombus is equal to the product of its base and its height, multiply 13 by 9 to see if it equals the area of the rhombus, 117 centimeters2: (13)(9) = 117 centimeters2.

28. Read the entire word problem.
29. We are given the area of a square and how it changes.

We are looking for the new area of the square.

Underline the keywords and words that indicate formulas.

The words area and square indicate that we must use the formula for area of a square, to find the length of one side of the square: A = s2.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

We can take the square root of the area to find the length of one side of the square. Then, we can double that length and use the area formula again to find the area of the new square.

Write number sentences for each operation.

First, take the square root of the area:

81

Solve the number sentences and decide which answer is reasonable.

81 = 9 feet

Write number sentences for each operation.

One side of the original square is 9 feet. To find the length of one side of the new square, multiply 9 by 2:

(9)(2)

Solve the number sentences and decide which answer is reasonable.

(9)(2) = 18 feet

Write number sentences for each operation.

One side of the new square is 18 feet. To find the area of the new square, square 18:

182

Solve the number sentences and decide which answer is reasonable.

182 = 324 square feet

If the length of a side of a square doubles, the area of the square increases by four times. Multiply the original area, 81 square feet, by 4 to see if it equals the new area: (81)(4) = 324 square feet.

30. Read the entire word problem.

We are looking for a diameter.

Underline the keywords and words that indicate formulas.

The words diameter and radius are keywords.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for diameter is d = 2r. Multiply the radius by 2 to find the diameter.

Write number sentences for each operation.

2(100)

Solve the number sentences and decide which answer is reasonable.

2(100) = 200 inches

Since diameter is twice the radius, divide the diameter by 2 to check that the radius is, in fact, 100 inches: = 2 inches.

31. Read the entire word problem.
32. We are given a radius.

We are looking for an area.

Underline the keywords and words that indicate formulas.

The words radius and area are keywords.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the area of a circle is A = 2πr2. Square the radius and multiply by π to find the area.

Write number sentences for each operation.

π(4)2

Solve the number sentences and decide which answer is reasonable.

π(4)2 = 16π inches2

Divide the area by π, and then take the square root of the quotient. This should give us back the radius, 4 feet: = 16, √16 = 4 feet.

33. Read the entire word problem.

We are given a circumference.

We are looking for a diameter.

Underline the keywords and words that indicate formulas.

The words circumference and diameter are keywords.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for circumference is C = πd, so we can find the diameter by dividing the circumference by π.

Write number sentences for each operation.

Solve the number sentences and decide which answer is reasonable.

= 18 units

Multiply the diameter by π. This should give us back the circumference: (18)(π) = 18π, so our answer is correct.

34. Read the entire word problem.

We are given an area.

We are looking for a diameter.

Underline the keywords and words that indicate formulas.

The words area and diameter are keywords.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the area of a circle is A = πr2, so we can find the radius by dividing the area by π, and then taking the square root of the quotient. Once we have the radius, we can multiply it by 2 to find the diameter.

Write number sentences for each operation.

Divide the area by π:

= 18 units

Solve the number sentences and decide which answer is reasonable.

= 144 square units

Write number sentences for each operation.

Find the radius by taking the square root of 144:

144

Solve the number sentences and decide which answer is reasonable.

144 = 12

The radius of the circle is 12 units. To find the diameter, multiply the radius by 2.

Write number sentences for each operation.

(12)(2)

Solve the number sentences and decide which answer is reasonable.

(12)(2) = 24 units

Divide the diameter by 2 to find the radius. Then, square the radius and multiply by π. This should give us back the area, 144π square units. = 12, π(12)2 = 144π square units.

35. Read the entire word problem.

We are given an area.

We are looking for a circumference.

Underline the keywords and words that indicate formulas.

The words area and circumference are keywords.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the area of a circle is A = πr2, so we can find the radius by dividing the area by π, and then taking the square root of the quotient. Once we have the radius, we can multiply it by 2π to find the circumference.

Write number sentences for each operation.

Divide the area by π:

Solve the number sentences and decide which answer is reasonable.

= 361 square units

Write number sentences for each operation.

Find the radius by taking the square root of 361:

361

Solve the number sentences and decide which answer is reasonable.

361 = 19

The radius of the circle is 19 units. To find the circumference, multiply the radius by 2π.

Write number sentences for each operation.

(19)(2π)

Solve the number sentences and decide which answer is reasonable.

(19)(2π) = 38πunits

Divide the circumference by 2π to find the radius. Then, square the radius and multiply by π. This should give us back the area, 361π square units. = 19, π(19)2 = 361π square units.

36. Read the entire word problem.

We are given the length, width, and height of a rectangular prism.

We are looking for its volume.

Underline the keywords and words that indicate formulas.

The words rectangular prism and volume are keywords. We will use the formula for the volume of a rectangular prism.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the volume of a rectangular prism is V = lwh, so we can multiply the three given values to find the volume.

Write number sentences for each operation.

(14)(9)(10)

Solve the number sentences and decide which answer is reasonable.

(14)(9)(10) = 1,260 inches3

Divide the volume by the length and the width. This should give us back the height: = 10 inches.

37. Read the entire word problem.

We are given the volume of a sphere.

We are looking for its radius.

Underline the keywords and words that indicate formulas.

The words sphere and volume are keywords. We will use the formula for the volume of a sphere prism to find the radius of the sphere.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the volume of a sphere is V = πr3. Divide both sides of the equation by π and take the cube root of both sides: r = 3. First, multiply the volume by 3. Then, divide that product by 4π. Finally, take the cube root of the result.

Write number sentences for each operation.

(3)(972π)

Solve the number sentences and decide which answer is reasonable.

(3)(972π) = 2,916π centimeters3

Write number sentences for each operation.

Divide 2,916 by 4π:

Solve the number sentences and decide which answer is reasonable.

= 728

Write number sentences for each operation.

Take the cube root of 729:

3√729

Solve the number sentences and decide which answer is reasonable.

3√729 = 9 centimeters

The radius of the sphere is 9 centimeters.

Plug the radius into the formula for the volume of a sphere. πr3 = π(9)3 = (729)π = 972π centimeters3.

38. Read the entire word problem.

We are given the radius and height of a cylinder.

We are looking for its volume.

Underline the keywords and words that indicate formulas.

The words cylinder and volume are keywords. We will use the formula for the volume of a cylinder.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the volume of a cylinder is V = πr2h, so we can square the radius and multiply by the height to find the volume.

Write number sentences for each operation.

π(8)2(12)

Solve the number sentences and decide which answer is reasonable.

π(8)2(12) = 768π feet3

Divide the volume by the height and π. Then, take the square root, and we should have the radius: = 64, √64 = 8 feet.

39. Read the entire word problem.

We are given the volume and height of a cone.

We are looking for its radius.

Underline the keywords and words that indicate formulas.

The words cone and volume are keywords. We will use the formula for the volume of a cone.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the volume of a cone is V = πr2h, so we can rewrite this equation to solve for r, the radius. Multiply both sides of the equation by 3 and divide by π and h. Then, take the square root of both sides.

Write number sentences for each operation.

First, multiply the volume by 3:

(300π)(3)

Solve the number sentences and decide which answer is reasonable.

(300π)(3) = 900π inches3

Write number sentences for each operation.

Next, divide that product by π and h:

Solve the number sentences and decide which answer is reasonable.

= 25 inches2

Write number sentences for each operation.

Finally, take the square root:

25

Solve the number sentences and decide which answer is reasonable.

25 = 5 inches

Plug the radius and height into the formula for volume of a cone. πr2h = π(5)2(36) = (25)π(36) = (25π)(12) = 300π inches3.

40. Read the entire word problem.

We are given the area of one side of a cube.

We are looking for the volume of the cube.

Underline the keywords and words that indicate formulas.

The words area, cube, and volume are keywords. We will use the formula for the area of a square and the formula for the volume of a cone.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

We must use the area of one side of the cube to find the length of one edge of the cube. Then, we can use that length to find the volume of the cube. Since the formula for the area of a square is A = s2, take the square root of the area to find the length of one side, or edge. The formula for the volume of a cube is V = e3, so we must then take the length of one edge and cube it to find the volume.

Write number sentences for each operation.

First, take the square root of the area:

2.56

Solve the number sentences and decide which answer is reasonable.

2.56 = 1.6 meters

Write number sentences for each operation.

Now, cube the length of one edge:

(1.6)3

Solve the number sentences and decide which answer is reasonable.

(1.6)3 = 4.096 meters3

Take the cube root of the volume to find the length of one edge, and then square that to find the area of one side of the cube: 3√4.096 = 1.6, (1.6) 2= 2.56 meters2.

41. Read the entire word problem.

We are given the radius and height of a cylinder.

We are looking for its surface area.

Underline the keywords and words that indicate formulas,.

The words cylinder and surface area are keywords. We will use the formula for the surface area of a cylinder.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the surface area of a cylinder is SA = 2πr2 + 2πrh, so we must begin by squaring the radius and multiplying it by 2π. Then, we must multiply the radius and the height by 2π. Finally, we must add those two products together.

Write number sentences for each operation.

First, square the radius and multiply it by 2π:

[(6)2](2π)

Solve the number sentences and decide which answer is reasonable.

[(6)2](2π) = (36)(2π) = 72π

Write number sentences for each operation.

Now, multiply the radius and the height by 2π:

(6)(18)(2π)

Solve the number sentences and decide which answer is reasonable.

(6)(18)(2π) = 216π

Write number sentences for each operation.

72π + 216π

Solve the number sentences and decide which answer is reasonable.

72π + 216π = 288π

Plug both the radius and the height into the surface area formula and do the calculations again to insure your answer is correct: 2π(6)2 + 2π(6)(18) = 72π + 216π = 288π.

42. Read the entire word problem.

We are given the surface area of a sphere.

We are looking for its radius.

Underline the keywords and words that indicate formulas.

The words sphere and surface area are keywords. We will use the formula for the surface area of a sphere to find the radius of the sphere.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the surface area of a sphere is SA = 4πr2, so we can rewrite it to solve for the radius by dividing both sides by 4π, and then taking the square root of both sides.

Write number sentences for each operation.

First, divide the surface area by 4π:

Solve the number sentences and decide which answer is reasonable.

= 53.29

Write number sentences for each operation.

Now, take the square root of 53.29:

53.29

Solve the number sentences and decide which answer is reasonable.

53.29 = 7.3

Plug the radius into the surface area formula to find the surface area of the sphere: 4πr2 = 4π(7.3)2 = 4π(53.29) = 213.16π millimeters3.

43. Read the entire word problem.

We are given the volume of a cube.

We are looking for its surface area.

Underline the keywords and words that indicate formulas.

The words cube, volume, and surface area are keywords. We will use the formula for the volume of a cube to find the edge of the cube, and then use the formula for surface area of a cube.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the volume of a cube is V = e3, so we can find the edge of the cube by taking the cube root of the volume. Since the formula for surface area of a cube is SA = 6s2, once we have the length of one edge, or side, we can square it and multiply by 6 to find the surface area.

Write number sentences for each operation.

First, take the cube root of 343:

3√343

Solve the number sentences and decide which answer is reasonable.

343 = 7 inches

Write number sentences for each operation.

Now, square that length and multiply by 6:

6(7)2

Solve the number sentences and decide which answer is reasonable.

6(7)2 = 6(49) = 294 inches2

Divide the surface area by 6 and take the square root. This will give us the length of one edge of the cube. Cube that length to get back the volume of the cube: = 49, 493 = 343 inches3.

44. Read the entire word problem.

We are given the length, width, and volume of a rectangular prism.

We are looking for its surface area.

Underline the keywords and words that indicate formulas.

The words rectangular prism, volume, and surface area are keywords. We will use the formula for the volume of a rectangular prism to find the height of the prism, and then use the formula for the surface area of a rectangular prism.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the volume of a rectangular prism is V = lwh. We can rewrite that as h = by dividing both sides of the equation by lw. Once we have the height of the rectangular prism, we can plug it, the length, and the width into the formula for the surface area of a rectangular prism: SA = 2(lw +wh + lh).

Write number sentences for each operation.

First, divide the volume by the product of the length and width to find the height:

Solve the number sentences and decide which answer is reasonable.

= 4.1 meters

rite number sentences for each operation.

The height of the prism is 4.1 meters. Now, plug the values of the length, width, and height into the formula for the surface area of a rectangular prism:

2[(3)(2.2) + (2.2)(4.1) + (3)(4.1)]

Solve the number sentences and decide which answer is reasonable.

2[(3)(2.2) + (2.2)(4.1) + (3)(4.1)] = 2(6.6 + 9.02 + 12.3) = 2(27.92) = 55.84 meters2

Check that the height you found, 4.1 meters, is correct by multiplying it by the length and width to see if it equals the given volume, 27.06 meters3: (3)(2.2)(4.1) = 27.06 meters3.

45. Read the entire word problem.

We are given the height and the area of the base of a cylinder.

We are looking for its surface area.

Underline the keywords and words that indicate formulas.

The words cylinder, area, and surface area are keywords. We will use the formula for the surface area of a cylinder.

Cross out extra information and translate words into numbers.

There is no extra information in this problem.

List the possible operations.

The formula for the surface area of a cylinder is SA = 2πr2 + 2πrh. The bases of a cylinder are circles, so the first part of the surface area formula, 2πr2, is equal to twice the area of the base. We are given the area of the base, so we can multiply that by 2 to find the first part of the surface area of the cylinder. To find the radius of the cylinder, we must divide the area of one base by π and then take the square root. Once we have the radius, we can multiply it by 2π and by the height, and this will give us the second part of the surface area. To find the total surface area, we will add the two parts together.

Write number sentences for each operation.

First, multiply the area of one base by 2:

(16π)(2)

Solve the number sentences and decide which answer is reasonable.

(16π)(2) = 32π

Write number sentences for each operation.

We have the first part of the surface area. Next, find the radius of the cylinder. Divide the area of one base by π and then take the square root:

Solve the number sentences and decide which answer is reasonable.

= 16

Write number sentences for each operation.

16

Solve the number sentences and decide which answer is reasonable.

16 = 4 centimeters

Write number sentences for each operation.

The radius is 4 centimeters. Multiply it by 2π and by the height to find, the second part of the surface area.

(2π)(4)(8)

Solve the number sentences and decide which answer is reasonable.

(2π)(4)(8) = 64π

Write number sentences for each operation.

Finally, add the first part of the surface area, the area of the bases, to the second part of the surface area, the area of the curved surface:

32π + 64π

Solve the number sentences and decide which answer is reasonable.

32π + 64π = 96π centimeters2

Plug both the radius and the height into the surface area formula:

2π(4)2 + 2π(4)(8) = 32π + 64π = 96π centimeters2.

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