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Simple Exponent and Logarithm Equations Help (page 3)

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Examples

Find the domain. Give your answers in interval notation.

  • f ( x ) = log 5 (2 − x )
  • Because we are taking the log of 2 − x , 2 − x needs to be positive.

    2 − x > 0

    x > − 2

    x < 2

    The domain is (−∞, 2).

  • f ( x ) = log( x 2x − 2)

x 2x − 2 > 0

( x − 2)( x + 1) > 0

Put x = 2 and x = − 1 on the number line and test to see where ( x − 2) ( x + 1) > 0 is true.

Exponents and Logarithms Exponent and Logarithm Equations (Part I)

Fig. 9.13

We want the “True” intervals, so the domain is (−∞, −1) ∪ (2, ∞).

  • g ( x ) = ln( x 2 + 1)

Because x 2 + 1 is always positive, the domain is all real numbers, (−∞, ∞).

Finding the Domain of a Function Practice Problems

Practice

Find the domain. Give your answers in interval notation.

  1. f ( x ) = ln(10 − 2 x )
  2. h ( x ) = log( x 2 − 4)
  3. f ( x ) = log( x 2 + 4)

Solutions

  1. Solve 10 − 2 x > 0. The domain is x < 5, (−∞, 5).
  2. Solve x 2 − 4 > 0

Exponents and Logarithms Exponent and Logarithm Equations (Part I)

Fig. 9.14

The domain is (−∞, −2) ∪ (2, ∞).

  1. Because x 2 + 4 > 0 is always positive, the domain is all real numbers, (—∞, ∞).

Find practice problems and solutions for these concepts at: Exponents and Logarithms Practice Test.

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