Examples

-
From above, we know that the x -axis, or the horizontal line y = 0, is a horizontal asymptote. Here is why. Because the highest power on x is 4, we will multiply the fraction by
which reduces to 1, so we are not changing the fraction.
For large values of x , 3/ x , 5/ x 2 , 1/ x 3 , 6/ x 4 , 8/ x 2 , and 1/ x 4 are very close to zero, so for large values of x ,

-

-
The degree of the numerator equals the degree of the denominator, so the graph of this function has a horizontal asymptote at the line y = 4/9. Here is why. Because the largest power on x is 3, we will multiply the fraction by
.
For large values of
is close to
.
These steps are not necessary to find the horizontal asymptotes, only the three rules earlier in this guide.
Rational Functions Practice Problems
Practice
Find the intercepts, vertical asymptotes, and horizontal asymptotes.

Solutions
-
The vertical is asymptote
, from 2 x + 3 = 0. The horizontal asymptote is
because the numerator and denominator have the same degree. The x -intercept is −2, from x + 2 = 0. The y -intercept is
-
The vertical asymptotes are x = − 5 and x = 4, from x 2 + x − 20 = 0. The horizontal asymptote is y = 0 because the denominator has the higher degree. The x -intercept is 0, from −3 x = 0. The y -intercept is

-
There is no vertical asymptote because x 2 + 1 = 0 has no real solution. The horizontal asymptote is y = 1/1 = 1 because the numerator and denominator have the same degree. The x -intercepts are ±1, from x 2 − 1 = 0. The y -intercept is

-
The vertical asymptote is
from 8 x + 3 = 0. There is no horizontal asymptote because the numerator has the higher degree. The x -intercepts are
, from 9 x 2 − 1 = 0. The y -intercept is
-
There is no vertical asymptote because x 2 + 4 = 0 has no real solution. There is no horizontal asymptote because the numerator has the higher degree. The x -intercept is −1, from x 3 + 1 = 0. The y -intercept is

-
The vertical asymptote is x = 0, from x 2 = 0. The horizontal asymptote y = 0 because the denominator has the higher degree. There is no x -intercept because the numerator is 2, never 0. There is no y -intercept because 2/0 2 is not defined.
Practice problems for this concept can be found at: Rational Functions Practice Test.
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. It has a vertical asymptote at the line x = 1 because x = 1 causes a zero in the denominator.
at x = 0.99 and x = 1.01, two x -values close to a zero in the denominator.
and 

, where a n is the leading coefficient of the numerator and b m is the leading coefficient of the denominator.
. The vertical line
is the vertical asymptote for this graph. There is no horizontal asymptote because the degree of the numerator, 2, is more than the degree of the denominator, 1. The x -intercepts are ±4 (from x 2 − 16 = 0) and the y -intercept is



because the degree of the numerator and denominator is the same. The x -intercept is 0 (from 3 x 2 = 0). The y -intercept is

, if we let x be any large number, the fraction will be close to 0.
is.
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