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Slope of a Line Practice Questions

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Updated on Oct 3, 2011

To review these concepts, go to Slope of a Line Study Guide.

Slope of a Line Practice Questions

Practice

  1. The endpoints of a line segment are (–3,6) and (7,4). What is the slope of this line?
  2. The endpoints of a line segment are (5,–5) and (–5,–5). What is the slope of this line?
  3. What is the slope of a line segment with endpoints at (–1,2) and (1,10)?
  4. What is the midpoint of a line segment with endpoints at (0,–8) and (–8,0)?
  5. What is the midpoint of a line segment with endpoints at (6,–4) and (15,8)?
  6. The endpoints of a line segment are (0,–4) and (0,4). What is the midpoint of this line?
  7. What is the distance from the point (–6,2) to the point (2,17)?
  8. What is the distance from the point (0,–4) to the point (4,4)?
  9. What is the distance from the point (3,8) to the point (7,–6)?

Solutions

  1. The slope of a line is the difference between the y values of two points divided by the difference between the x values of those two points:

    .

  2. The slope of a line is the difference between the y values of two points divided by the difference between the x values of those two points:

    .

  3. The slope of a line is the difference between the y values of two points divided by the difference between the x values of those two points:

    .

  4. The midpoint of a line segment is equal to the average of the x values of the endpoints and the average of the y values of the endpoints:

    .

  5. The midpoint of a line segment is equal to the average of the x values of the endpoints and the average of the y values of the endpoints:

    .

  6. The midpoint of a line is equal to the average of the x values of the endpoints and the average of the y values of the endpoints:

    .

  7. To find the distance between two points, use the distance formula:

    D = √(x2x1)2 + (y2y1)2

    D = √ (2 – (– 6))2 + (17 – 2)2

    D = √ (82 + (15)2

    D = √ 64 + 225

    D = √ 289 = 17 units

  8. To find the distance between two points, use the distance formula:

    D = √ (x2x1)2 + (y2y1)2

    D = √ (4 – 0)2 + (4 – (– 4))2

    D = √ 42 + 82

    D =√ 16 + 64

    D = √ 80 = √ 16 × √ 5 = 4 √5 units

  9. To find the distance between two points, use the distance formula:

    D = √ (x2x1)2 + (y2y1)2

    D = √ (7 – 3)2 + ((– 6) – 8)2

    D = √ 42 + (– 14)2

    D = √ 16 + 196

    D = √ 212 = √ 4 × √ 53 = 2√ 53 units

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