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# Solving Simple Algebraic Equations Practice Questions (page 2)

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#### Practice 2

1. To find x in terms of y, we must get x alone on one side of the equation, with y on the other side of the equal sign. In the equation x + 4 = y – 6, 4 is added to x. Use the opposite operation, subtraction, to get x alone on one side of the equation. Subtract 4 from both sides of the equation:

x + 4 – 4 = y – 6 – 4

x = y – 10

The value of x, in terms of y, is y – 10.

2. To find x in terms of y, we must get x alone on one side of the equation, with y on the other side of the equal sign. In the equation 2x = 8y, x is multiplied by 2. Use the opposite operation, division, to get x alone on one side of the equation. Divide both sides of the equation by 2:

x = 4y

The value of x, in terms of y, is 4y.

3. To find x in terms of y, we must get x alone on one side of the equation, with y on the other side of the equal sign. In the equation x – 7 = 3y, 7 is subtracted from x. Use the opposite operation, addition, to get x alone on one side of the equation. Add 7 to both sides of the equation:

x – 7 + 7 = 3y + 7

x = 3y + 7

The value of x, in terms of y, is 3y + 7.

4. To find x in terms of y, we must get x alone on one side of the equation, with y on the other side of the equal sign. In the equation = y + 1, x is divided by 9. Use the opposite operation, multiplication, to get x alone on one side of the equation. Multiply both sides of the equation by 9:

9 = 9(y + 1)

Use the distributive law to find 9(y + 1). Multiply 9 by y and multiply 9 by 1.

(9)(y) = 9y, (9)(1) = 9

x = 9y + 9

The value of x, in terms of y, is 9y + 9.

5. To find x in terms of y, we must get x alone on one side of the equation, with y on the other side of the equal sign. In the equation 3x = –12y + 15, x is multiplied by 3. Use the opposite operation, division, to get x alone on one side of the equation. Divide both sides of the equation by 3:

x = –4y + 5

The value of x, in terms of y, is –4y + 5.

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