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More Electronics Information for ASVAB Power Practice Problems (page 2)

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  1. c. Data stored on magnetic tape can be lost by exposure to heat; damage can also be done by stretching the tape or by exposure toother magnetic fields.
  2. b. Current is the rate at which an electrical charge passes a specific point in a circuit.
  3. d. In a series circuit, the total resistance is the sum of each resistor value. 7 resistors × 67Ω = 469Ω.
  4. b. In a parallel circuit, the total resistance is the value of a single resistor.
  5. a. The symbol actually shows a single-pole 4-way switch.
  6. a. Ohms is the resistance of the current and amperes is the strength of the current.
  7. c. AC stands for alternating current.
  8. b. DC stands for direct current.
  9. d. The coating process used in electroplating is known as electrodeposition.
  10. c. This is the schematic symbol for a lamp.
  11. d. RMS stands for root mean square, which is the peak value of voltage multiplied by 0.707.
  12. b. This is the schematic symbol for a battery.
  13. a. The velocity of radio waves radiated into free space is 300,000,000 meters per second, which is the speed of light. Choice c, 343 meters per second, is the speed of sound.
  14. d. Volts = ohms × amps. V = 10 × 20. V = 200.
  15. b. Water is not an insulator. Rubber is another insulator not listed in the choices.
  16. c. Dielectric heating is the process by which a dielectric material is subjected to a rapidly altering electrical field. Heat is generated as the radio wave or microwave electromagnetic radiation heats the material.
  17. a. A zener diode is used to regulate voltage. A photodiode (b) converts light to electricity, a capacitor (c) stores electricity, and a light emitting diode (d) converts electricity to light.
  18. d. This is the schematic symbol for a ground.
  19. c. The neutral wire is white or silver in 120-volt wiring in the United States. The hot or live wire can be black, red, blue, or brass. Orange or yellow wire is often used for input signals.
  20. b. Watts = amps × volts. W = 30 × 120. W = 3,600.
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